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42-11x=x^2
We move all terms to the left:
42-11x-(x^2)=0
determiningTheFunctionDomain -x^2-11x+42=0
We add all the numbers together, and all the variables
-1x^2-11x+42=0
a = -1; b = -11; c = +42;
Δ = b2-4ac
Δ = -112-4·(-1)·42
Δ = 289
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{289}=17$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-11)-17}{2*-1}=\frac{-6}{-2} =+3 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-11)+17}{2*-1}=\frac{28}{-2} =-14 $
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